IND vs AUS: Rohit Sharma’s blast in Nagpur, became the only player in Team India’s victory


Team India got victory in Nagpur
Rohit Sharma is the hero of victory
Unbeaten innings of 46 runs

New Delhi. The second match of the ongoing three-match T20 International series between India and Australia was played at the Vidarbha Cricket Association Stadium in Nagpur today. In this match, the Indian team came back and defeated the hosts by six wickets. With this, Blue Army has also leveled 1-1 in the three-match T20I series. During the match, Indian team captain Rohit Sharma was seen in tremendous form, and took the team alone to the threshold of victory.

In fact, KL Rahul came to the field with Sharma to chase down the target of 91 runs given by the Australian team. However, Rahul failed to play a big innings and became the victim of Adam Zampa by scoring just 10 runs. After Rahul, veteran batsman Virat Kohli (11) who came in the field also became the second victim of Zampa in the affair of scoring fast runs. Not only this, Suryakumar Yadav, the third batsman who came in the field, could not last long and without opening the account became LBW on the ball of Zampa.

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Captain Sharma’s courage did not break even in the midst of the wickets falling continuously in the field and he stood at one end. He played an important role in winning the team in the last moments, sharing important partnerships with Hardik Pandya (9) and Dinesh Karthik (10 *).

Captain Rohit Sharma faced a total of 20 balls while opening the innings today. During this, he played an unbeaten explosive innings of 46 runs at a strike rate of 230.00. During this, four fours and four high-rise sixes came from his bat. Due to this explosive innings of Sharma, the Indian team easily achieved the target of 91 runs at the loss of four wickets with four balls to spare.

Tags: India vs Australia, Indian Cricket Team, Indian team, Rohit Sharma

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