Everything is at stake for Mumbai Indians in the 55th match of IPL 2021. Leave the match here against Sunrisers Hyderabad, even if Rohit Sharma loses the toss, then Mumbai’s work will be spoiled. To make it to the playoffs, Rohit’s platoon will have to thrash Hyderabad by at least 171 runs, ie, a total of more than 200 on the score board. But, the lives of Mumbai fans are stuck in the toss, as if the toss goes in favor of Kane Williamson, the defending champions will have to pack their bags from UAE. Why are we saying this, let us explain to you in detail.
In fact, Mumbai Indians have to beat Hyderabad by a margin of 171 runs to make it to the playoffs and leave KKR behind in the net run rate. But it is important that captain Rohit Sharma also wins the toss, because if Williamson decides to bat first after winning the toss, then this decision taken by the Hyderabad captain will end five-time champions Mumbai’s journey in IPL 2021. According to the equation made for the playoffs, if Mumbai bowls first, then they cannot leave KKR behind in any case in terms of net run rate. Fans of Mumbai Indians will now pray that the toss fell in Rohit’s favor before the team’s miraculous victory.
However, even if Mumbai Indians win the toss and bat first, then the team will have to change the history of IPL to register a win. The biggest defeat in IPL has been 146 runs and Rohit’s team has to beat Hyderabad by 171 runs. That is, batting first, Mumbai will have to score at least close to 250 and then expect their bowlers to all out SRH for 70 or 80 runs. The place of the defending champion in the playoffs does not seem to be made at any cost, but cricket is said to be a game of uncertainties and there have been many such charisma that seemed impossible to imagine.